process.arts - Comments for "Calculating the point at which a piece of box section steel will bend and not recover." https://process.arts.ac.uk/content/calculating-point-which-piece-box-section-steel-will-bend-and-not-recover Comments for "Calculating the point at which a piece of box section steel will bend and not recover." en You haven't considered the https://process.arts.ac.uk/content/calculating-point-which-piece-box-section-steel-will-bend-and-not-recover#comment-3822 <p>You haven't considered the weight of the steel itself. As the leverage gets greater, the affect will rise dramatically.</p> Mon, 26 Dec 2016 11:35:37 +0000 Anonymous comment 3822 at https://process.arts.ac.uk Excellent reply. Makes me https://process.arts.ac.uk/content/calculating-point-which-piece-box-section-steel-will-bend-and-not-recover#comment-3610 <p>Excellent reply.</p> <p>Makes me realise just how fortunate I was to get the answer right in the first place. As I said, I had a lot of support from physics forum as my desire to find the answer far outweighed my ability.</p> <p>I'll make these changes in due course and genuinely appreciate your comments.</p> <p>All the best</p> <p>Steve</p> Tue, 01 Apr 2014 12:29:04 +0000 swood comment 3610 at https://process.arts.ac.uk Hi - thanks for the article - https://process.arts.ac.uk/content/calculating-point-which-piece-box-section-steel-will-bend-and-not-recover#comment-3608 <p>Hi - thanks for the article - the primary formula is one I had been looking for.</p> <p>As a high school and college teacher of physics, I wanted to point out some misconceptions with your units. Torque (or moment of turning) is measured in Nm (Newton x meters).</p> <p>Weight (A force due to gravity) is kilograms times 9.81 meters divided by seconds square. The unit of weight is the Newton (N)</p> <p>All length units must be the same - you converted cm to the 4th to mm to the 4th, but because you had meters elsewhere, you should have converted mm and cm to the 4th to meters and meters to the 4th.</p> <p>As for why multiplying both sides by 15600 got rid of the /15600, remember that a number divided by itself is 1, so 15600/15600 = 1.</p> <p>In the end you got the correct answer (mine was .5089 meters which is the same as yours in mm).</p> <p>I tried to answer using the data with superscripts, but could not figure out how to produce superscripts!</p> <p>Again, thanks for the article. David V. Fansler <a href="mailto:dfansler@dv-fansler.com">dfansler@dv-fansler.com</a></p> Tue, 25 Mar 2014 01:19:47 +0000 Anonymous comment 3608 at https://process.arts.ac.uk HiJohn Thanks for this https://process.arts.ac.uk/content/calculating-point-which-piece-box-section-steel-will-bend-and-not-recover#comment-1429 <p>HiJohn</p> <p>Thanks for this endorsment.</p> <p>Steve</p> Fri, 09 Mar 2012 14:20:02 +0000 swood comment 1429 at https://process.arts.ac.uk Hi  I love this! It is so https://process.arts.ac.uk/content/calculating-point-which-piece-box-section-steel-will-bend-and-not-recover#comment-1427 <p>Hi </p> <p>I love this! It is so clear and useful. Long Long ago I studied Physics and Mechanics and I was right back there reading about 'moments' etc.</p> <p> </p> <p>Thanks</p> <p>John</p> Fri, 09 Mar 2012 11:25:24 +0000 jcasey comment 1427 at https://process.arts.ac.uk